Lucas reagent is equimolar solution of

Question

Lucas reagent is equimolar solution of (A) cone. H2SO4 and cone. HNO3 (B) cone. HNO3 and anhydrous ZnCl3 (C) cone. HCl and anhydrous ZnCl2 (D) cone. H2SO4 and anhydrous ZnCl2

Tardigrade Admin · Accepted Answer

Lucas reagent is a solution of saturated and anhydrous zinc chloride in concentrated hydrochloric acid. This solution is used to classify alcohols of low molecular weight. The reaction is a substitution in which the chloride replaces a hydroxyl group.

Q. Lucas reagent is equimolar solution of

cone. $H_{2} S O_{4}$ and cone. $H N O_{3}$

cone. $H N O_{3}$ and anhydrous $Z n C l_{3}$

cone. $H Cl$ and anhydrous $Z n C l_{2}$

cone. $H_{2} S O_{4}$ and anhydrous $Z n C l_{2}$

Lucas reagent is a solution of saturated and anhydrous zinc chloride in concentrated hydrochloric acid. This solution is used to classify alcohols of low molecular weight. The reaction is a substitution in which the chloride replaces a hydroxyl group.

Q. Lucas reagent is equimolar solution of

cone. H2​SO4​ and cone. HNO3​

cone. HNO3​ and anhydrous ZnCl3​

cone. HCl and anhydrous ZnCl2​

cone. H2​SO4​ and anhydrous ZnCl2​

Lucas reagent is a solution of saturated and anhydrous zinc chloride in concentrated hydrochloric acid. This solution is used to classify alcohols of low molecular weight. The reaction is a substitution in which the chloride replaces a hydroxyl group.

cone. $H_{2} S O_{4}$ and cone. $H N O_{3}$

cone. $H N O_{3}$ and anhydrous $Z n C l_{3}$

cone. $H Cl$ and anhydrous $Z n C l_{2}$

cone. $H_{2} S O_{4}$ and anhydrous $Z n C l_{2}$