Locus of the point of intersection of perpendicular tangents to the circle x2 + y2 = 16 is

Question

Locus of the point of intersection of perpendicular tangents to the circle x2 + y2 = 16 is (A) x2 + y2 = 8  (B) x2 + y2 = 32  (C)  x2 + y2 = 64 (D) x2 + y2 = 16.

Tardigrade Admin · Accepted Answer

Correct answer is (b) x2 + y2 = 32

Q. Locus of the point of intersection of perpendicular tangents to the circle $x^{2} + y^{2} = 16$ is

$x^{2} + y^{2} = 8$

$x^{2} + y^{2} = 32$

$x^{2} + y^{2} = 64$

$x^{2} + y^{2} = 16.$

Correct answer is (b) $x^{2} + y^{2} = 32$

Q. Locus of the point of intersection of perpendicular tangents to the circle x2+y2=16 is

x2+y2=8

x2+y2=32

x2+y2=64

x2+y2=16.

Correct answer is (b) x2+y2=32

Q. Locus of the point of intersection of perpendicular tangents to the circle $x^{2} + y^{2} = 16$ is

$x^{2} + y^{2} = 8$

$x^{2} + y^{2} = 32$

$x^{2} + y^{2} = 64$

$x^{2} + y^{2} = 16.$

Correct answer is (b) $x^{2} + y^{2} = 32$