Liquids A and B are at 30 ° C and 20 ° C respectively. When mixed in equal masses, the temperature of the mixture is found to be 26 ° C . Their specific heats are in the ratio of

Question

Liquids A and B are at 30 ° C and 20 ° C respectively. When mixed in equal masses, the temperature of the mixture is found to be 26 ° C . Their specific heats are in the ratio of (A) 3:2 (B) 1:1 (C) 2:3 (D) 4:3

Tardigrade Admin · Accepted Answer

According to principle of calorimetry, Heat given = Heat taken ⇒ msA(30 - t)=msB(t - 20) ⇒ (sA/sB)=(6/4)=(3/2)

Q. Liquids $A$ and $B$ are at $30^{\circ} C$ and $20^{\circ} C$ respectively. When mixed in equal masses, the temperature of the mixture is found to be $26^{\circ} C$ . Their specific heats are in the ratio of

$3 : 2$

$1 : 1$

$2 : 3$

$4 : 3$

According to principle of calorimetry,
Heat given = Heat taken
$\Rightarrow m s_{A} (30 - t) = m s_{B} (t - 20)$
$\Rightarrow \frac{s _{A}}{s _{B}} = \frac{6}{4} = \frac{3}{2}$

Q. Liquids A and B are at 30∘C and 20∘C respectively. When mixed in equal masses, the temperature of the mixture is found to be 26∘C . Their specific heats are in the ratio of

3:2

1:1

2:3

4:3