lionization energy of hydrogen atom is 13.6 texteV text. textIf texth=6 text.6 ! !× ! ! text 1 text0 text-34 textJoule-sec, then value of R (Rydberg constant) will be:

Question

lionization energy of hydrogen atom is 13.6 texteV text. textIf texth=6 text.6 ! !× ! ! text 1 text0 text-34 textJoule-sec, then value of R (Rydberg constant) will be: (A)  1010 per metre (B)  107 per metre (C)  104 per metre (D)  10-7 per metre

Tardigrade Admin · Accepted Answer

Rydberg constant R=-(E/ch) =-(13.6× 1.6× 10-19/3× 108× 6.6× 10-34) =107 per metre

Q. lionization energy of hydrogen atom is 13.6 $eV . If h=6 .6 \times 1 0^{-34} Joule-sec,$ then value of R (Rydberg constant) will be:

$10^{10}$ per metre

$10^{7}$ per metre

$10^{4}$ per metre

$10^{- 7}$ per metre

Rydberg constant $R = - \frac{E}{c h}$ $= - \frac{13.6 \times 1.6 \times 10 ^{- 19}}{3 \times 10 ^{8} \times 6.6 \times 10 ^{- 34}}$ $= 10^{7}$ per metre

Q. lionization energy of hydrogen atom is 13.6 eV.Ifh=6.6 × 10-34Joule-sec, then value of R (Rydberg constant) will be:

1010 per metre

107 per metre

104 per metre

10−7 per metre