Question

${\lim }_{x\to 3}\frac{|x-3|}{x-3}$is

• A. 1
• B. -1
• C. 0
• D. does not exist.

Answer 1

Answer: (B)

${\lim }_{x\to 3}\frac{|x-3|}{x-3}={\lim }_{x\to 3}\frac{-\left(x-3\right)}{x-3}=-1$