Question

$\underset{x\to 0}{\lim }\frac{tan2x-x}{3x-sinx}=$

Answer 1

Answer: 0.5

$\underset{x\to 0}{\lim }\frac{tan2x-x}{3x-sinx}$
$=\underset{x\to 0}{\lim }\left\{\frac{\frac{2tan2x-1}{2x}}{3-\frac{sinx}{x}}\right\}$
$=\frac{2-1}{3-1}=\frac{1}{2}=0.5$