Light of wavelength 600 nm is incident on an aperture of size 2 mm. The distance upto which light can travel such that its spread is less than the size of the aperture is

Question

Light of wavelength 600 nm is incident on an aperture of size 2 mm. The distance upto which light can travel such that its spread is less than the size of the aperture is (A) 12.13 m (B) 6.67 m (C) 3.33 m (D) 2.19 m

Tardigrade Admin · Accepted Answer

The distance upto which light can travel is Fresnel distance, zF = (d2/λ) =((2× 10-3)2/600 × 10-9) = 6.67 m

Q. Light of wavelength $600 nm$ is incident on an aperture of size $2 mm$ . The distance upto which light can travel such that its spread is less than the size of the aperture is

$12.13 m$

$6.67 m$

$3.33 m$

$2.19 m$

The distance upto which light can travel is
Fresnel distance, $z_{F} = \frac{d ^{2}}{λ}$
$= \frac{( 2 \times 1 0 ^{- 3} ) ^{2}}{600 \times 1 0 ^{- 9}} = 6.67 m$

Q. Light of wavelength 600nm is incident on an aperture of size 2mm. The distance upto which light can travel such that its spread is less than the size of the aperture is

12.13m

6.67m

3.33m

2.19m