Light of wavelength 4000 mathringA falls on a photosensitive metal and a negative 2 V potential stops the emitted electrons. The work function of the material (in eV ) is approximately (h=6.6 × 10-34 Js , e=1.6 × 10-19 C. . c=3 × 108 ms -1)

Question

Light of wavelength 4000 mathringA falls on a photosensitive metal and a negative 2 V potential stops the emitted electrons. The work function of the material (in eV ) is approximately (h=6.6 × 10-34 Js , e=1.6 × 10-19 C. . c=3 × 108 ms -1) (A) 1.1 (B) 2.0 (C) 2.2 (D) 3.1

Tardigrade Admin · Accepted Answer

Energy of incident light E( eV )=(12375/4000)=3.09 eV Stopping potential is -2 V so K max =2 eV Hence by using E=W0+K max ⇒ W0=1.09 eV ≈ 1.1 eV

Q. Light of wavelength $4000 \overset{˚}{A}$ falls on a photosensitive metal and a negative $2 V$ potential stops the emitted electrons. The work function of the material (in $e V$ ) is approximately $(h = 6.6 \times 1 0^{- 34} J s, e = 1.6 \times 1 0^{- 19} C$ $c = 3 \times 1 0^{8} m s^{- 1})$

1.1

2.0

2.2

3.1

Energy of incident light $E (e V) = \frac{12375}{4000} = 3.09 e V$
Stopping potential is $- 2 V$ so $K_{m a x} = 2 e V$
Hence by using $E = W_{0} + K_{m a x}$
$\Rightarrow W_{0} = 1.09 e V \approx 1.1 e V$

Q. Light of wavelength 4000A˚ falls on a photosensitive metal and a negative 2V potential stops the emitted electrons. The work function of the material (in eV ) is approximately (h=6.6×10−34Js,e=1.6×10−19C c=3×108ms−1)

1.1

2.0

2.2

3.1

Energy of incident light E(eV)=400012375​=3.09eV Stopping potential is −2V so Kmax​=2eV Hence by using E=W0​+Kmax​ ⇒W0​=1.09eV≈1.1eV

Q. Light of wavelength $4000 \overset{˚}{A}$ falls on a photosensitive metal and a negative $2 V$ potential stops the emitted electrons. The work function of the material (in $e V$ ) is approximately $(h = 6.6 \times 1 0^{- 34} J s, e = 1.6 \times 1 0^{- 19} C$ $c = 3 \times 1 0^{8} m s^{- 1})$

Energy of incident light $E (e V) = \frac{12375}{4000} = 3.09 e V$
Stopping potential is $- 2 V$ so $K_{m a x} = 2 e V$
Hence by using $E = W_{0} + K_{m a x}$
$\Rightarrow W_{0} = 1.09 e V \approx 1.1 e V$