Light of frequency v falls on material of threshold frequency v0 . Maximum kinetic energy of emitted electron is proportional to :

Question

Light of frequency v falls on material of threshold frequency v0 . Maximum kinetic energy of emitted electron is proportional to : (A)  V-V0  (B)  V  (C)  √V-V0  (D)  V0

Tardigrade Admin · Accepted Answer

When light falls on a metallic surface, ejection of photoelectron results. In this process, conservation of energy hold.
Thus, from law of conservation of energy,
energy imparted by the photon = maximum kinetic energy of the emitted electron + work function of the metal
or

h v = (K E)_{ma x} + ϕ

but

ϕ = h v_{0}, v_{0}

being threshold frequency.
or

(K E)_{ma x} = h v - h v_{0}

or

(K E)_{ma x} \propto v - v_{0}

Q. Light of frequency $v$ falls on material of threshold frequency $v_{0}$ . Maximum kinetic energy of emitted electron is proportional to :

$V - V_{0}$

$V$

$V - V_{0}$

$V_{0}$

Q. Light of frequency v falls on material of threshold frequency v0​ . Maximum kinetic energy of emitted electron is proportional to :

V−V0​

V

V−V0​​

V0​

Q. Light of frequency $v$ falls on material of threshold frequency $v_{0}$ . Maximum kinetic energy of emitted electron is proportional to :

$V - V_{0}$

$V$

$V - V_{0}$

$V_{0}$