Light of frequency 1.5 times the threshold frequency is incident on a photosensitive material. What will be the photoelectric current if the frequency is halved and intensity is doubled?

Question

Light of frequency 1.5 times the threshold frequency is incident on a photosensitive material. What will be the photoelectric current if the frequency is halved and intensity is doubled? (A) doubled (B) four times (C) one-fourth (D) zero

Tardigrade Admin · Accepted Answer

K1=1.5 hv0-φ0=0.5 hv0 K2=(1.5/2)hv0-hv0=-0.25 hv0 ∵ Kinetic energy can never be negative, so no emission and i=0

Q. Light of frequency 1.5 times the threshold frequency is incident on a photosensitive material. What will be the photoelectric current if the frequency is halved and intensity is doubled?

doubled

four times

one-fourth

zero

$K_{1} = 1.5 h v_{0} - ϕ_{0} = 0.5 h v_{0}$
$K_{2} = \frac{1.5}{2} h v_{0} - h v_{0} = - 0.25 h v_{0}$
$∵$ Kinetic energy can never be negative, so no emission and $i = 0$

Q. Light of frequency 1.5 times the threshold frequency is incident on a photosensitive material. What will be the photoelectric current if the frequency is halved and intensity is doubled?

doubled

four times

one-fourth

zero

K1​=1.5hv0​−ϕ0​=0.5hv0​ K2​=21.5​hv0​−hv0​=−0.25hv0​ ∵ Kinetic energy can never be negative, so no emission and i=0

$K_{1} = 1.5 h v_{0} - ϕ_{0} = 0.5 h v_{0}$
$K_{2} = \frac{1.5}{2} h v_{0} - h v_{0} = - 0.25 h v_{0}$
$∵$ Kinetic energy can never be negative, so no emission and $i = 0$