Li nucleus has three protons and four neutrons. Mass of lithium nucleus is 7.016005 amu. Mass of proton is 1.007277 amu and mass of neutron is 1.008665 amu. Mass defect for lithium nucleus in amu is

Question

Li nucleus has three protons and four neutrons. Mass of lithium nucleus is 7.016005 amu. Mass of proton is 1.007277 amu and mass of neutron is 1.008665 amu. Mass defect for lithium nucleus in amu is (A) 0.04048 (B) 0.04050 (C) 0.04052 (D) 0.04055

Tardigrade Admin · Accepted Answer

Mass defect = mass of nucleons - mass of nucleus =(3× 1.007277+4× 1.008665)-7.016005 =0.040486 textamu ≈ 0.04050 textamu

Q. Li nucleus has three protons and four neutrons. Mass of lithium nucleus is 7.016005 amu. Mass of proton is 1.007277 amu and mass of neutron is 1.008665 amu. Mass defect for lithium nucleus in amu is

0.04048

0.04050

0.04052

0.04055

Mass defect = mass of nucleons - mass of nucleus
$= (3 \times 1.007277 + 4 \times 1.008665) - 7.016005$
$= 0.040486 amu$
$\approx 0.04050 amu$

Q. Li nucleus has three protons and four neutrons. Mass of lithium nucleus is 7.016005 amu. Mass of proton is 1.007277 amu and mass of neutron is 1.008665 amu. Mass defect for lithium nucleus in amu is

0.04048

0.04050

0.04052

0.04055

Mass defect = mass of nucleons - mass of nucleus =(3×1.007277+4×1.008665)−7.016005 =0.040486amu ≈0.04050amu

Mass defect = mass of nucleons - mass of nucleus
$= (3 \times 1.007277 + 4 \times 1.008665) - 7.016005$
$= 0.040486 amu$
$\approx 0.04050 amu$