Question

Let$S=\left\{x\in [-6,3]-\{-2,2\}:\frac{|x+3|-1}{|x|-2}\ge 0\right\}$ and $T=\left\{x\in Z:x^2-7|x|+9\le 0\right\}$. Then the number of elements in $S\cap T$ is

• A. 7
• B. 5
• C. 4
• D. 3

Answer 1

Answer: (D)

$S\cap T=\{-5,-4,3\}$