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Q. Let$S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\}$ and $T=\left\{x \in Z: x^2-7|x|+9 \leq 0\right\}$. Then the number of elements in $S \cap T$ is

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Solution:

$S \cap T =\{-5,-4,3\}$