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Tardigrade
Question
Mathematics
Let y=f(x), x ∈ R satisfies the differential equation x(y prime prime+y prime)=-y prime-e-x and y(0)=-1 where y prime=( dy / dx ) and y prime prime=( d 2 y / dx 2). The value of ∫01 ex(f(x)+3) d x is equal to
Q. Let
y
=
f
(
x
)
,
x
∈
R
satisfies the differential equation
x
(
y
′′
+
y
′
)
=
−
y
′
−
e
−
x
and
y
(
0
)
=
−
1
where
y
′
=
d
x
d
y
and
y
′′
=
d
x
2
d
2
y
.
The value of
∫
0
1
e
x
(
f
(
x
)
+
3
)
d
x
is equal to
46
100
Application of Integrals
Report Error
A
e
B
e
−
1
C
3
D
1
Solution:
Correct answer is (a) e