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Tardigrade
Question
Mathematics
Let Y = 1,2,3,4,5 A = 1, 2 B = 3,4,5 and φ denotes null set. If (A × B) denotes cartesian product of the sets A and B , then (Y × A) ∩ (7 × B) is
Q. Let
Y
=
{
1
,
2
,
3
,
4
,
5
}
,
A
=
{
1
,
2
}
,
B
=
{
3
,
4
,
5
}
and
ϕ
denotes null set. If
(
A
×
B
)
denotes cartesian product of the sets
A
and
B
, then
(
Y
×
A
)
∩
(
7
×
B
)
is
2188
225
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A
Y
B
A
C
B
D
ϕ
Solution:
Given that,
Y
=
{
1
,
2
,
3
,
4
,
5
}
A
=
{
1
,
2
}
B
=
{
3
,
4
,
5
}
∴
(
Y
×
A
)
=
{(
1
,
1
)
,
(
1
,
2
)
,
(
2
,
1
)
,
(
2
,
2
)
,
(
3
,
1
)
,
(
3
,
2
)
(
4
,
1
)
,
(
4
,
2
)
,
(
5
,
1
)
,
(
5
,
2
)}
and
(
Y
×
B
)
=
{(
1
,
3
)
,
(
1
,
4
)
,
(
1
,
5
)
,
(
2
,
3
)
,
(
2
,
4
)
,
(
2
,
5
)
,
(
3
,
3
)
,
(
3
,
4
)
,
(
3
,
5
)
,
(
4
,
3
)
,
(
4
,
4
)
,
(
4
,
5
)
,
(
5
,
3
)
,
(
5
,
4
)
,
(
5
,
5
)}
Now,
(
Y
×
A
)
∩
(
Y
×
B
)
=
ϕ
(null set)