Q.
Let the tangent drawn to the parabola y2=24x at the point (α,β) is perpendicular to the line 2x+2y=5. Then the normal to the hyperbola α2x2−β2y2=1 at the point (α+4,β+4) does NOT pass through the point :
Tangent at (α,β) has slope 1 β2=24α
Equation of tangent yβ=12(x+α),β12=1 ⇒α=6,β=12 ∴(α+4,β+4)=(10,16)
Normal at (10,16) to 36x2−144y2=1 is 2x+5y=100