Let the relation R is defined in N by a R b, if 3 a+2 b=27 then R is

Question

Let the relation R is defined in N by a R b, if 3 a+2 b=27 then R is (A)  (1,12)(3,9)(5,6)(7,3)  (B)  (1,12)(3,9)(5,6)(7,3)(9,0)  (C)  (0, (27/2))(1,12)(3,9)(5,6)(7,3)  (D)  (2,1)(9,3)(6,5)(3,7)

Tardigrade Admin · Accepted Answer

2 b =27-3 a b =(27-3 a /2) R = (1,2),(3,9),(5,6),(7,3)

Q. Let the relation $R$ is defined in $N$ by $a R b$ , if $3 a + 2 b = 27$ then $R$ is

${(1, 12) (3, 9) (5, 6) (7, 3)}$

${(1, 12) (3, 9) (5, 6) (7, 3) (9, 0)}$

${(0, \frac{27}{2}) (1, 12) (3, 9) (5, 6) (7, 3)}$

${(2, 1) (9, 3) (6, 5) (3, 7)}$

$2 b = 27 - 3 a$
$b = \frac{27 - 3 a}{2}$
$R = {(1, 2), (3, 9), (5, 6), (7, 3)}$

Q. Let the relation R is defined in N by aRb, if 3a+2b=27 then R is

{(1,12)(3,9)(5,6)(7,3)}

{(1,12)(3,9)(5,6)(7,3)(9,0)}

{(0,227​)(1,12)(3,9)(5,6)(7,3)}

{(2,1)(9,3)(6,5)(3,7)}