Let the minimum external work done in shifting a particle from centre of earth to earthâs surface be W1 and that from surface of earth to infinity be W2. Then (W1/W2) is equal to

Question

Let the minimum external work done in shifting a particle from centre of earth to earthâs surface be W1 and that from surface of earth to infinity be W2. Then (W1/W2) is equal to (A) 1: 1 (B) 1: 2 (C) 2: 1 (D) 1: 3

Tardigrade Admin · Accepted Answer

(W1/W2) = (-(GM/R) -(-(3/2) (GM/R))/0 - (- (GM)R)) = (1/2)

Q. Let the minimum external work done in shifting a particle from centre of earth to earth’s surface be $W_{1}$ and that from surface of earth to infinity be $W_{2}$ . Then $\frac{W _{1}}{W _{2}}$ is equal to

$1 : 1$

$1 : 2$

$2 : 1$

$1 : 3$

$\frac{W _{1}}{W _{2}} = \frac{- \frac{GM}{R} - ( - \frac{3}{2} \frac{GM}{R} )}{0 - ( - \frac{GM}{R} )} = \frac{1}{2}$

Q. Let the minimum external work done in shifting a particle from centre of earth to earth’s surface be W1​ and that from surface of earth to infinity be W2​. Then W2​W1​​ is equal to

1:1

1:2

2:1

1:3