Q.
Let the focal length of the objective and eye lens be 1.2cm and 3cm , respectively. Let the object is put 1.25cm away from the objective lens and the final image is formed at infinity. What is the magnifying power of the microscope?
The microscope here, is a compound microscope which is a combination of objective and eyepiece.
For the objective lens, fo1=vo1−uo1
Objective lens is convex, so fo=1.2cm +1.21=vo1−(−1.25)1+1.21=vo1+1.251vo1=1.21−1.251vo=30cm
When final image is at infinity,
Net magnification, m=mo×me m=uovo×feD m=−1.2530×325∣m∣=200