Q.
Let the coefficients of third, fourth and fifth terms in the expansion of (x+x2a)n,x=0, be in the ratio 12:8:3. Then the term independent
of x in the expansion, is equal to ______.
Tr+1=nCr(x)n−r(x2a)r =nCraTxn−3r nC2a2:nC3a3:nC4a4=12:8:3
After solving n=6,a=21
For term independent of 'x' ⇒n=3r r=2 ∴ Coefficient is 6C2(21)2=415
Nearest integer is 4.