Tardigrade
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Tardigrade
Question
Mathematics
Let Sk be sum of an infinite G.P. whose first term is k and common ratio is (1/k+1). Then displaystyle∑k=110 Sk is equal to
Q. Let
S
k
be sum of an infinite
G
.
P
. whose first term is
k
and common ratio is
k
+
1
1
. Then
k
=
1
∑
10
S
k
is equal to ____
2063
211
Sequences and Series
Report Error
Answer:
65
Solution:
S
k
=
1
−
k
+
1
1
k
=
k
+
1
k
=
1
∑
10
S
k
=
k
=
1
∑
10
(
k
+
1
)
=
2
10
×
11
+
10
=
65