Let 3x=t;t>0 t(t−1)+2=∣t−1∣+∣t−2∣ t2−t+2=∣t−1∣+∣t−2∣ Case-I :t<1<br/>t2−t+2=1−t+2−t t2+2=3−t t2+t−1=0 t=2−1±5 t=25−1 is only acceptable Case-II :1≤t<2<br/>t2−t+2=t−1+2−t t2−t+1=0 D<0 no real solution Case-III :t≥2 t2−t+2=t−1+t−2 t2−3t5=0⇒D<0 no real solution