Here, the relation on set of positive real numbers is S={(x,y)∣2y≤x≤2y}
Let (x,x)∈S, then 2x≤x≤2x ⇒xSx S is reflexive.
Now, let (x,y)∈S such that xSy ⇒2y≤x≤2y ∵2y≤x and x≤2y ⇒y≤2x and 2x≤y ⇒2x≤y≤2x ⇒ySx S is symmetric.
Note that (3,4)∈S&(4,7)∈S
but (3,7)∈/S S is not transitive.