Question

Let $R_1=\{(x,y):y\le |x|\}$ and $R_2=\left\{(x,y):x^2+y^2\le 2\right\}$, then the area of region $R_1\cap R_2$ equals

• A. $\frac{\pi }{2}$
• B. $\pi$
• C. $\frac{3\pi }{2}$
• D. $2\pi$

Answer 1

Answer: (C)

Correct answer is (c) $\frac{3\pi }{2}$