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Question
Physics
Let r1(t)=3 t i+4 t2 j and r2(t)=4 t2 i+3 r j represent the positions of particles 1 and 2 , respectively, as function of time t, r1(t) and r2(t) are in meter and t in second. The relative speed of the two particles at the instant t =1 s, will be
Q. Let
r
1
(
t
)
=
3
t
i
+
4
t
2
j
and
r
2
(
t
)
=
4
t
2
i
+
3
r
j
represent the positions of particles
1
and
2
, respectively, as function of time
t
,
r
1
(
t
)
and
r
2
(
t
)
are in meter and
t
in second. The relative speed of the two particles at the instant
t
=
1
s
, will be
2223
192
AMU
AMU 2012
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A
1
m
/
s
B
3
2
m
/
s
C
5
2
m
/
s
D
7
2
m
/
s
Solution:
Given,
r
1
(
t
)
=
3
t
i
+
4
t
2
j
∴
d
t
d
r
1
=
3
i
+
8
t
j
At
t
=
1
s
v
1
=
d
t
d
r
1
=
3
i
+
8
j
Again,
r
2
(
t
)
=
4
t
2
i
+
3
t
j
d
t
d
r
2
=
8
t
i
+
3
j
At
t
=
1
s
v
2
=
d
t
d
r
2
=
8
i
+
3
j
Relative velocity
=
v
1
−
v
2
=
−
5
i
=
5
j
=
(
5
)
2
+
(
5
)
2
=
5
2
m
/
s