Question

Let $P(x)=\left|\begin{array}{ccc}{x}^2-13& 4& 2\\ 3& x^2-13& 7\\ 6& 5& x^2-13\end{array}\right|$
If $x=-2$ is a zero of $P(x)$, then sum of the remaining five zeros is

• A. -2
• B. 0
• C. 2
• D. 3

Answer 1

Answer: (C)

As coefficient of $x^5$ in $P(x)$ is 0 , sum of six zeros of $P(x)$ is 0
. $\Rightarrow$ sum of the remaining five zeros $+(-2)=0$
$\Rightarrow$ sum of the remaining five zeros $=2$.