Tardigrade
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Tardigrade
Question
Mathematics
Let p , q , r and s be four positive numbers such that pqrs =1, then the least value of (1+p)(1+q)(1+r)(1+s) is equal to
Q. Let
p
,
q
,
r
and
s
be four positive numbers such that pqrs
=
1
, then the least value of
(
1
+
p
)
(
1
+
q
)
(
1
+
r
)
(
1
+
s
)
is equal to
189
130
Sequences and Series
Report Error
A
4
B
16
C
64
D
256
Solution:
A.M.
≥
G.M. (for positive numbers)