Q.
Let orthocentre of ΔABC is (4,6) . If A=(4,7) and B=(−2,4) , then coordinates of vertex C is
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Solution:
Let feet of altitudes through A,B,C are D,E,F respectively.
Now, C lies on the line CF,CA & CB
Now, the slope of AD is 4−47−6=N.D. ⇒ the slope of BC is 0 ⇒ equation of BC is y=4
Now, the slope of BE is 4−(−2)6−4=31 ⇒ the slope of AC is −3 ⇒ equation of the line AC is (y−7)=−3(x−4)
Point of intersection of y=4 and y−7=−3(x−4) gives point C ⇒C=(5,4)