Let O be the origin and A be the point (64, 0). If P, Q divide OA in the ratio 1: 2: 3 , then the point P is

Question

Let O be the origin and A be the point (64, 0). If P, Q divide OA in the ratio 1: 2: 3 , then the point P is (A) ((32/3),0) (B) ( 32, 0 ) (C) ((64/3),0) (D) ( 16, 0)

Tardigrade Admin · Accepted Answer

Now, by internal section formula, <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/40647d0f1929cee9a4848c5067930766-.png" /> P ≡((1 × 64+5 × 0/1+5), (1 × 0+5 × 0/1+5)) ≡((64/6), 0)=((32/3), 0)

Q. Let $O$ be the origin and $A$ be the point $(64, 0) .$ If $P$ , $Q$ divide $O A$ in the ratio $1 : 2 : 3$ , then the point $P$ is

$(\frac{32}{3}, 0)$

( 32, 0 )

$(\frac{64}{3}, 0)$

( 16, 0)

$(\frac{16}{3}, 0)$

Now, by internal section formula,

$P \equiv (\frac{1 \times 64 + 5 \times 0}{1 + 5}, \frac{1 \times 0 + 5 \times 0}{1 + 5})$
$\equiv (\frac{64}{6}, 0) = (\frac{32}{3}, 0)$

Q. Let O be the origin and A be the point (64,0). If P, Q divide OA in the ratio 1:2:3 , then the point P is

(332​,0)