Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Let n (U) = 700, n (A) = 200, n (B) = 300, n (A ∩ B) = 100, then n (A' ∩ B') is equal to
Q. Let
n
(
U
)
=
700
,
n
(
A
)
=
200
,
n
(
B
)
=
300
,
n
(
A
∩
B
)
=
100
, then
n
(
A
′
∩
B
′
)
is equal to
3174
207
Sets
Report Error
A
400
14%
B
600
16%
C
300
60%
D
None of these
10%
Solution:
n
(
A
′
∩
B
′
)
=
n
(
A
∪
B
)
′
=
n
(
U
)
−
n
(
A
∪
B
)
=
n
(
U
)
−
[
n
(
A
)
+
n
(
B
)
−
n
(
A
∩
B
)]
=
700
−
[
200
+
300
−
100
]
=
300