1. Tardigrade
  2. Question
  3. Mathematics
  4. Let n (U) = 700, n (A) = 200, n (B) = 300, n (A ∩ B) = 100, then n (A' ∩ B') is equal to

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Let $n (U) = 700, n (A) = 200, n (B) = 300, n (A \cap B) = 100$, then $n (A' \cap B')$ is equal to

Sets

Solution:

$n (A' \cap B') = n (A \cup B)' = n (U) - n (A \cup B)$
$= n (U) - [n (A) + n (B) - n (A \cap B)]$
$= 700 - [200 + 300 - 100] = 300$