Question

Let $\left(\begin{array}{c}n\\ k\end{array}\right)$ represents the combination of $n$ things taken $k$ at a time. The value of $\left(\genfrac{}{}{0ex}{}{100}{98}\right)+\left(\genfrac{}{}{0ex}{}{99}{97}\right)+\left(\genfrac{}{}{0ex}{}{98}{96}\right)+\left(\genfrac{}{}{0ex}{}{97}{95}\right)+......+\left(\genfrac{}{}{0ex}{}{4}{2}\right)+\left(\genfrac{}{}{0ex}{}{3}{1}\right)+\left(\genfrac{}{}{0ex}{}{2}{0}\right)$equals

• A. 15050
• B. 101000
• C. 151500
• D. 166650

Answer 1

Answer: (D)

Correct answer is (d) 166650