Q.
Let n be a fixed positive integer. Let a relation R be defined in I (the set of all integers) as follows : aRb iff n∣(a−b), that is, iff a - b is divisible by n. Then, the relation R is
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Relations and Functions - Part 2
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Solution:
Reflexive : Since for any integer a, we have a−a=0 is divisible by n. Hence, aRa∀a∈I. ∴R is Reflexive.
Symmetric : Let aRb. Then, by definition of R, a−b=nk, where k∈I. b−a=(−k)n where −k∈I and so bRa. ∴R is symmetric.
Transitive : Let aRb and bRc. Then, by definition of R, we have, a−b=k1n and b−c=k2n, where k1, k2∈I.
Then it follows that a−c=(a−b)+(b−c)=k1n+k2n−(k1+k2)n, where k1+k2∈I and so aRc. ∴R is transitive.
Hence, R is an equivalence relation.