Let log 10 2= a and log 10 3= b then Column I Column II A log 10( sin 2 (5 π/3)) equals P (4(2 a+b)/1-a+2 b) B log 100 4+2 log 100 27 equals Q (2 b 2+3 a 2/ ab ) C log 2 9+ log 3 8 equals R a+3 b D log √45 144 equals S b -2 a

Question

Let log 10 2= a and log 10 3= b then Column I Column II A log 10( sin 2 (5 π/3)) equals P (4(2 a+b)/1-a+2 b) B log 100 4+2 log 100 27 equals Q (2 b 2+3 a 2/ ab ) C log 2 9+ log 3 8 equals R a+3 b D log √45 144 equals S b -2 a (A) (A) S; (B) R; (C) Q; (D) P (B) (A) S; (B) R; (C) Q; (D) Q (C) (A) S; (B) R; (C) Q; (D) R (D) (A) S; (B) R; (C) Q; (D) S

Tardigrade Admin · Accepted Answer

Correct answer is (a) (A) S; (B) R; (C) Q; (D) P

Column I		Column II
A	$lo g_{10} (sin^{2} \frac{5 π}{3})$ equals	P	$\frac{4 ( 2 a + b )}{1 - a + 2 b}$
B	$lo g_{100} 4 + 2 lo g_{100} 27$ equals	Q	$\frac{2 b ^{2} + 3 a ^{2}}{ab}$
C	$lo g_{2} 9 + lo g_{3} 8$ equals	R	$a + 3 b$
D	$lo g_{45} 144$ equals	S	$b - 2 a$

Q. Let log10​2=a and log10​3=b then Column I Column II A log10​(sin235π​) equals P 1−a+2b4(2a+b)​ B log100​4+2log100​27 equals Q ab2b2+3a2​ C log2​9+log3​8 equals R a+3b D log45​​144 equals S b−2a

(A) S; (B) R; (C) Q; (D) P

(A) S; (B) R; (C) Q; (D) Q

(A) S; (B) R; (C) Q; (D) R

(A) S; (B) R; (C) Q; (D) S

Correct answer is (a) (A) S; (B) R; (C) Q; (D) P