Let K be the set of all real values of x where the function f(x) = sin |x| - |x| + 2(x - π ) cos |x| is not differentiable. Then the set K is equal to :

Question

Let K be the set of all real values of x where the function f(x) = sin |x| - |x| + 2(x - π ) cos |x| is not differentiable. Then the set K is equal to : (A)  π  (B)  0  (C) φ (an empty set) (D)  0 , π

Tardigrade Admin · Accepted Answer

f(x) = sin|x|-|x| + 2(x - π) cos x ∵ sin | x | - |x| is differentiable function at x = 0 ∴ k = φ

Q. Let $K$ be the set of all real values of $x$ where the function $f (x) = sin ∣ x ∣ - ∣ x ∣ + 2 (x - π) cos ∣ x ∣$ is not differentiable. Then the set $K$ is equal to :

${π}$

{ 0 }

$ϕ$ (an empty set)

${0, π}$

$f (x) = sin ∣ x ∣ - ∣ x ∣ + 2 (x - π) cos x$
$∵ sin ∣ x ∣ - ∣ x ∣$ is differentiable function at $x = 0$
$∴ k = ϕ$

Q. Let K be the set of all real values of x where the function f(x)=sin∣x∣−∣x∣+2(x−π)cos∣x∣ is not differentiable. Then the set K is equal to :

{π}

{ 0 }

ϕ (an empty set)

{0,π}

f(x)=sin∣x∣−∣x∣+2(x−π)cosx ∵sin∣x∣−∣x∣ is differentiable function at x=0 ∴k=ϕ

Q. Let $K$ be the set of all real values of $x$ where the function $f (x) = sin ∣ x ∣ - ∣ x ∣ + 2 (x - π) cos ∣ x ∣$ is not differentiable. Then the set $K$ is equal to :

${π}$

$ϕ$ (an empty set)

${0, π}$

$f (x) = sin ∣ x ∣ - ∣ x ∣ + 2 (x - π) cos x$
$∵ sin ∣ x ∣ - ∣ x ∣$ is differentiable function at $x = 0$
$∴ k = ϕ$