Question

Let graph of $f(x)=a{x}^2+bx+c$ is as shown in figure.

$\left|\frac{b^2}{4a}\right|-|c|$ is

• A. Positive
• B. zero
• C. negative
• D. can't say

Answer 1

Answer: (A)

$\left|\frac{b^2}{4a}\right|-|c|=-\frac{b^2}{4a}+c=\frac{-\left[b^2-4ac\right]}{4a}>0$