Question

Let graph of $f(x)=a x^{2}+b x+c$ is as shown in figure.

$\left|\frac{b^{2}}{4 a}\right|-|c|$ is

• A. Positive
• B. zero
• C. negative
• D. can't say

Answer 1

Answer: (A)

$\left|\frac{b^{2}}{4 a}\right|-|c|=-\frac{b^{2}}{4 a}+c=\frac{-\left[b^{2}-4 a c\right]}{4 a}>0$