Let γ1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ2 be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, (γ1/γ2) is :

Question

Let &gamma;1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and &gamma;2 be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, (&gamma;1/&gamma;2) is : (A) (21/25) (B) (25/21) (C) (35/27) (D) (27/35)

Tardigrade Admin · Accepted Answer

For monoatomic gas &gamma;1=(5/3) For diatomic gas at low temperatures &gamma;2=(7/5) ∴ (&gamma;1/&gamma;2)=((5/3)/(7)5)=(25/21)

Q. Let $γ_{1}$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $γ_{2}$ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, $\frac{γ _{1}}{γ _{2}}$ is :

$\frac{21}{25}$

$\frac{25}{21}$

$\frac{35}{27}$

$\frac{27}{35}$

For monoatomic gas $γ_{1} = \frac{5}{3}$
For diatomic gas at low temperatures
$γ_{2} = \frac{7}{5}$
$∴ \frac{γ _{1}}{γ _{2}} = \frac{\frac{5}{3}}{\frac{7}{5}} = \frac{25}{21}$

Q. Let γ1​ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ2​ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, γ2​γ1​​ is :

2521​

2125​

2735​

3527​