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Question
Mathematics
Let function f(x)=x4+ax3+bx2+cx+d such that f(- 1)=100,f(- 2)=200,f(- 3)=300 then the value (f (10) + f (- 14)/16) equals
Q. Let function
f
(
x
)
=
x
4
+
a
x
3
+
b
x
2
+
c
x
+
d
such that
f
(
−
1
)
=
100
,
f
(
−
2
)
=
200
,
f
(
−
3
)
=
300
then the value
16
f
(
10
)
+
f
(
−
14
)
equals
40
154
NTA Abhyas
NTA Abhyas 2022
Report Error
Answer:
2599
Solution:
f
(
x
)
=
(
x
+
1
)
(
x
+
2
)
(
x
+
3
)
(
x
+
t
)
−
100
x
for some
t
P
=
16
(
11
×
12
×
13
(
10
+
t
)
−
1000
)
+
(
−
13
×−
12
×−
11
×
(
t
−
14
)
+
1400
)
=
16
11
×
12
×
13
×
24
+
400
=
2599