Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Let f(x)= begincasesx2-2|x|+a, x ≤ 1 6+x, x >1 endcases, then number of positive integral value(s) of ' a ' for which f(x) has local minima at x=1, is/are
Q. Let
f
(
x
)
=
{
x
2
−
2∣
x
∣
+
a
,
6
+
x
,
x
≤
1
x
>
1
, then number of positive integral value(s) of '
a
' for which
f
(
x
)
has local minima at
x
=
1
, is/are
584
123
Application of Derivatives
Report Error
A
6
B
7
C
8
D
9
Solution:
a
−
1
≤
7
⇒
a
≤
8