Let f(x)= begincases √x2-1, x ≤ √10 (√10 x-7), √10

Question

Let f(x)= begincases √x2-1, x ≤ √10 (√10 x-7), √10 < x < 5 sin (π x), 5 ≤ x < 6 x 6 ≤ x ≤ 7 endcases Then the number of points where f(x) is discontinuous in [1,7] is [Note: x denotes fractional part of x.] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

f(x) is discontinuous in [1,7] at two points viz. x=5,7

Q. Let $f (x) = ⎩ ⎨ ⎧ x^{2} - 1, (10 x - 7), sin (π x), {x}, x \leq 10 10 < x < 5 5 \leq x < 6 6 \leq x \leq 7$
Then the number of points where $f (x)$ is discontinuous in $[1, 7]$ is
[Note: ${x}$ denotes fractional part of $x$ .]

$f (x)$ is discontinuous in $[1, 7]$ at two points viz. $x = 5, 7$

Q. Let f(x)=⎩⎨⎧​x2−1​,(10​x−7),sin(πx),{x},​x≤10​10​<x<55≤x<66≤x≤7​ Then the number of points where f(x) is discontinuous in [1,7] is [Note: {x} denotes fractional part of x.]

f(x) is discontinuous in [1,7] at two points viz. x=5,7

Q. Let $f (x) = ⎩ ⎨ ⎧ x^{2} - 1, (10 x - 7), sin (π x), {x}, x \leq 10 10 < x < 5 5 \leq x < 6 6 \leq x \leq 7$
Then the number of points where $f (x)$ is discontinuous in $[1, 7]$ is
[Note: ${x}$ denotes fractional part of $x$ .]

$f (x)$ is discontinuous in $[1, 7]$ at two points viz. $x = 5, 7$