Let f(x)=5 operatornamesgn(ex)-4(x-2)2 / 3. Then [Note: sgn k denotes signum function of k.]

Question

Let f(x)=5 operatornamesgn(ex)-4(x-2)2 / 3. Then [Note: sgn k denotes signum function of k.] (A) f(x) is increasing in (2, ∞) (B) f(x) is decreasing in (-∞, 2) (C) f(x) has minima at x=2 (D) f(x) has maxima at x=2

Tardigrade Admin · Accepted Answer

Correct answer is (d) f(x) has maxima at x=2

Q. Let $f (x) = 5 sgn (e^{x}) - 4 (x - 2)^{2/3}$ . Then
[Note: sgn k denotes signum function of k.]

$f (x)$ is increasing in $(2, \infty)$

$f (x)$ is decreasing in $(- \infty, 2)$

$f (x)$ has minima at $x = 2$

f(x) $ha s ma x imaa t$ x=2$

Correct answer is (d) f(x) $ha s ma x imaa t$ x=2$

Q. Let f(x)=5sgn(ex)−4(x−2)2/3. Then [Note: sgn k denotes signum function of k.]

f(x) is increasing in (2,∞)

f(x) is decreasing in (−∞,2)

f(x) has minima at x=2

f(x)hasmaximaatx=2$