Question

Let $f(x)=1+x$, $g(x)=x^2+x+1$, then $(f+g)(x)$ at $x=0$ is

• A. $2$
• B. $5$
• C. $6$
• D. $9$

Answer 1

Answer: (A)

We have, $f\left(x\right)=1+x$,
$g\left(x\right)=x^2+x+1$
$\therefore \left(f+g\right)\left(x\right)=f\left(x\right)+g\left(x\right)$
$=1+x+x^2+x+1<br/>=x^2+2x+2$
$\therefore \left(f+g\right)\left(0\right)=0^2+2\left(0\right)+2$
$=2$