Let f(x)=1-√x2 where the square root is to be taken positive, then

Question

Let f(x)=1-√x2 where the square root is to be taken positive, then (A) f has no extrema at x=0 (B) f has minima at x=0 (C) f has maxima at x=0 (D) f' exists at 0

Tardigrade Admin · Accepted Answer

f(x)=1-|x|, f has maxima at x=0

Q. Let $f (x) = 1 - x^{2}$ where the square root is to be taken positive, then

$f$ has no extrema at $x = 0$

$f$ has minima at $x = 0$

$f$ has maxima at $x = 0$

$f^{'}$ exists at 0

$f (x) = 1 - ∣ x ∣, f$ has maxima at $x = 0$

Q. Let f(x)=1−x2​ where the square root is to be taken positive, then

f has no extrema at x=0

f has minima at x=0

f has maxima at x=0

f′ exists at 0

f(x)=1−∣x∣,f has maxima at x=0

Q. Let $f (x) = 1 - x^{2}$ where the square root is to be taken positive, then

$f$ has no extrema at $x = 0$

$f$ has minima at $x = 0$

$f$ has maxima at $x = 0$

$f^{'}$ exists at 0

$f (x) = 1 - ∣ x ∣, f$ has maxima at $x = 0$