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Mathematics
Let f(x)=1-√x2 where the square root is to be taken positive, then
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Q. Let $f(x)=1-\sqrt{x^{2}}$ where the square root is to be taken positive, then
WBJEE
WBJEE 2020
A
$f$ has no extrema at $x=0$
B
$f$ has minima at $x=0$
C
$f$ has maxima at $x=0$
D
$f'$ exists at 0
Solution:
$f(x)=1-|x|, f$ has maxima at $x=0$