Tardigrade
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Tardigrade
Question
Mathematics
Let f(θ)=| cos 2 θ cos θ sin θ - sin θ cos θ sin θ sin 2 x cos θ sin θ - cos θ 0| then f((π/6))=
Q. Let
f
(
θ
)
=
∣
∣
cos
2
θ
cos
θ
sin
θ
sin
θ
cos
θ
sin
θ
sin
2
x
−
cos
θ
−
sin
θ
cos
θ
0
∣
∣
then
f
(
6
π
)
=
131
93
Determinants
Report Error
A
0
B
1
C
2
D
none
Solution:
Correct answer is (b) 1