1. Tardigrade
  2. Question
  3. Mathematics
  4. Let f(θ)=| cos 2 θ cos θ sin θ - sin θ cos θ sin θ sin 2 x cos θ sin θ - cos θ 0| then f((π/6))=

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Q. Let $f(\theta)=\begin{vmatrix}\cos ^2 \theta & \cos \theta \sin \theta & -\sin \theta \\ \cos \theta \sin \theta & \sin ^2 x & \cos \theta \\ \sin \theta & -\cos \theta & 0\end{vmatrix}$ then $f\left(\frac{\pi}{6}\right)=$

Determinants

Solution:

Correct answer is (b) 1