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Question
Mathematics
Let f: R - 0,1 arrow R be a function such that f(x)+f((1/1-x))=1+x. Then f(2) is equal to
Q. Let
f
:
R
−
{
0
,
1
}
→
R
be a function such that
f
(
x
)
+
f
(
1
−
x
1
)
=
1
+
x
. Then
f
(
2
)
is equal to
986
134
JEE Main
JEE Main 2023
Relations and Functions
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A
3
7
35%
B
2
9
20%
C
4
9
33%
D
4
7
13%
Solution:
f
(
x
)
+
f
(
1
−
x
1
)
=
1
+
x
x
=
2
⇒
f
(
2
)
+
f
(
−
1
)
=
3
(1)
x
=
−
1
⇒
f
(
−
1
)
+
f
(
2
1
)
=
0
(2)
x
=
2
1
⇒
f
(
2
1
)
+
f
(
2
)
=
2
3
(3)
(
1
)
+
(
3
)
−
(
2
)
⇒
2
f
(
2
)
=
2
9
∴
f
(
2
)
=
4
9