Q.
Let f be a function satisfying f(xy)=yf(x) for all positive real numbers x and y. If f(30)=20, then the value of f(40) is
1047
111
Relations and Functions - Part 2
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Solution:
An equation of this kind is called a functional equation, and can often be solved by choosing particular values for the variables. In this case, by choosing x=1, we see that f(y)=yf(1) for all y. put y =30;f(1)=30⋅f(30)=30⋅20=600 . Now f(40)=40f(1)=40600=15