Q.
Let f(a)=g(a)=k and their nth derivatives fn(a),gn(a) exist and are not equal for some n. Further if x→alimg(x)−f(x)f(a)g(x)−f(a)−g(a)f(x)+f(a)=4
then the value of k is
2470
190
Continuity and Differentiability
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Solution:
x→alimg′(x)−f′(x)f(a)g′(x)−g(a)f′(x)=4
(By L’ Hospital rule) x→alimg′(x)−f′(x)kg′(x)−kf′(x)=4∴k=4